Please Help: 25 Points!Jeremy constructed this solid by combining two rectangular prisms and a square pyramid. What is the surface area of this figure?
Accepted Solution
A:
Triangle area: A1 = (1/2) * (6) * (7) A1 = 21 Rectangle area of the base: A2 = (14) * (6) A2 = 84 Area of the posterior rectangle: A3 = (5) * (6) A3 = 30 Area of the frontal rectangle: A4 = (6) * (2) A4 = 12 Area of the rectangle parallel to the base: A5 = (8) * (6) A5 = 48 Rectangle area located between posterior and front rectangles: A6 = (3) * (6) A6 = 18 Area of the side walls of the figure: A7 = (14) * (2) + (3) * (6) A7 = 28 + 18 A7 = 46 Superficial area: A = 4 * A1 + A2 + A3 + A4 + A5 + A6 + 2 * A7 A = 4 * 21 + 84 + 30 + 12 + 48 + 18 + 2 * 46 A = 368 Answer: A = 368 m ^ 2