The function f(x)=5(x−1) is shown on the coordinate plane. Select from the drop-down menus to correctly describe the end behavior of f(x) . As x decreases without bound, the graph of f(x) . As x increases without bound, the graph of f(x) . An exponential curve graphed on a coordinate plane with horizontal x-axis ranging from negative 4 to 4 in increments of 1. The vertical y-axis ranges from negative 5 to 5 in increments of 1. The curve begins from the second quadrant. The curve increases through begin ordered pair 0 comma 0.2 end ordered pair. The curve passes through begin ordered pair 1 comma 1 end ordered pair and moves away from the positive y-axis.
Accepted Solution
A:
Answer: As x decreases without bound the graph f(x) decreases, as x increases without bound the graph of f(x) increases.Step-by-step explanation:Since, the given function is , [tex]f(x) =5(x-1)[/tex]If [tex]x\rightarrow -\infty[/tex] then [tex]f(x)\rightarrow -\infty[/tex]that is, we can say, as x decreases without bound the graph f(x) decreases.While, If [tex]x\rightarrow +\infty[/tex] then [tex]f(x)\rightarrow +\infty[/tex]That is, we can say, as x increases without bound the graph f(x) increases.thus, we can say first option represents the correct end behavior of f(x).