40 pts! and brainliest Submarine A is positioned at –1,100 feet in relation to sea level. Submarine B is positioned at –800 feet in relation to sea level. Each submarine needs to be 200 feet below sea level in 30 minutes. Which compares the speeds at which each submarine needs to travel?Submarine A must travel at a rate of (blank) ft/min, and Submarine B must travel at a rate of (blank) ft/min.
Accepted Solution
A:
Answer:43.3333.33Step-by-step explanation:Speed = distance/timeNow, submarine A is presently 1100ft away from sea level and still needs to cover a distance of 200ft below sea level. The total distance it needs to cover is 1100 + 200 = 1300ftSubmarine B is at a distance of 800ft above sea level and still needs to go 200ft below. Total distance needed to be covered is 800 + 200 = 1000ft.The speed of submarine A = 1300/30 = 43.33ft/minThe speed of submarine B = 1000/30 = 33.33ft/min